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Consider an xv6-like filesystem where: blocks are 512 bytes inodes contain 12 direct block pointers and 1 indirect block pointer block pointers take up 2 bytes directory entries are 32 bytes Question 3 (2 points) (see above) To access the 10000th byte of a file, the OS needs to lookup the indirect pointer of the inode for the file to find an array of block pointers, then access the block at index (where the first index is index 0) of that array of block pointers.
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Consider an xv6-like filesystem where: blocks are 512 bytes inodes contain 12 direct block pointers...
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