(4 points) In general, it is not true that eAeB = eA+B, which diers when compared to the exponential function for real numbers. (However, if A and B commute, that is, if AB = BA, then the above relation does hold.) Show, using the matrices A = 2 4 0 1 7 0 0 2 0 0 0 3 5 B = 2 4 0 1 1 0 0 3 0 0 0 3 5 that eAeB 6= eA+B. To calculate eA and eB, use the fact that A3 = 03 and B3 = 03.