Consider the regular expressions: R1 = (01)* (0*1*) (10)
R2 = (101)* (01)*
R3 = (10) (01*)*(01)
R4 = 10(R2*)|R3

Recall that, for a list of regular expressions, the function getToken() returns the next token from the input that matches one of the regular expressions. If there is more than one match, the longest match is returned. If there is more than one longest match, the token with the longest match that appears first in the list is returned. If there is no match, ERROR is returned. If the function getToken() is called once on input 1000101, it will return:

a. R1
b. R2
c. R3
d. R4
e. ERROR

What is a rush associated with alcohol?

In three to five sentences, describe how you can organize written information logically and sequentially

The idea that, for each pair of devices v and w, there’s a strict dichotomy between being “in range” or “out of range” is a simplified abstraction. more accurately, there’s a power decay function f (·) that specifies, for a pair of devices at distance δ, the signal strength f(δ) that they’ll be able to achieve on their wireless connection. (we’ll assume that f (δ) decreases with increasing δ.) we might want to build this into our notion of back-up sets as follows: among the k devices in the back-up set of v, there should be at least one that can be reached with very high signal strength, at least one other that can be reached with moderately high signal strength, and so forth. more concretely, we have values p1 ≥ p2 ≥ . . ≥ pk, so that if the back-up set for v consists of devices at distances d1≤d2≤≤dk,thenweshouldhavef(dj)≥pj foreachj. give an algorithm that determines whether it is possible to choose a back-up set for each device subject to this more detailed condition, still requiring that no device should appear in the back-up set of more than b other devices. again, the algorithm should output the back-up sets themselves, provided they can be found.\