Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither. The input begins with an integer indicating the number of integers that follow. Assume that the list will always contain less than 20 integers. Ex: If the input is:

5 2 4 6 8 10
the output is:

all even
Ex: If the input is:

5 1 3 5 7 9
the output is:

all odd
Ex: If the input is:

5 1 2 3 4 5
the output is:

not even or odd
Your program must define and call the following two functions. IsArrayEven returns true if all integers in the array are even and false otherwise. IsArrayOdd returns true if all integers in the array are odd and false otherwise.

bool IsArrayEven(int inputVals[], int numVals)

bool IsArrayOdd(int inputVals[], int numVals)

#include

#include

/* Define your function here */

int main(void) {

/* Type your code here. Remember to include the bool library*/

return 0;

}

Explanation:

Not sure what level that's at, or how you're expected to manage memory, so I'll write it in a "safe" manner and you can adjust accordingly.

Notably, I'm allocating memory dynamically at the moment.  If you're not used to that, you might want to change that.  Also, the c compiler I'm using (gcc) doesn't handle the bool type, so I used int.  You may need to change that.

Also, if you change it to use fixed arrays instead of malloc, realloc and free, then you don't need to include stdlib.h.

The code below builds successfully with gcc, so if you have any issues, it will be in translating to another compiler/language.

#include <stdio.h>

#include <stdlib.h>

int isArrayOdd(int *inputVals, int numVals){

       int n, rval = 1;

       for(n = 0; n < numVals && rval; n++){

               rval &= inputVals[n] & 1;

       }  

       return rval;

}

int isArrayEven(int *inputVals, int numVals){

       int n, rval = 1;

       for(n = 0; n < numVals && rval; n++){

               rval &= 1 - (inputVals[n] & 1);

       }  

       return rval;

}

int main(void) {

       /*  

               I'm writing this to allow any quantity of numbers,

               using malloc to allocate the memory for them dynamically.

               You may want to modify this to match the level that your

               class is in.

       */

       int *numbers, quantity = 0, input;

       numbers = (int *) malloc(sizeof(int));

       printf("Please enter a number, or hit \"q\" to quit: ");

       while(scanf("%i", &input) == 1){

               quantity++;

               numbers = (int *) realloc(numbers, quantity * sizeof(int));

               numbers[quantity - 1] = input;

               printf("\nyou entered %i\n", numbers[quantity - 1]);

       }  

       if(isArrayOdd(numbers, quantity)){

               printf("all odd\n");

       }else if(isArrayEven(numbers, quantity)){

               printf("all even\n");

       }else{

               printf("not even or odd\n");

       }  

       free(numbers);

       return 0;

}

BONUS!    BONUS!    BONUS!    BONUS!    BONUS!    BONUS!    BONUS!

The inefficiency of the logic dictated in the assignment drove me nuts, so here's one that's ridiculously simpler and does exactly the same job:

#include <stdio.h>

int main(void) {

       int input, oddEven = -1;

       printf("Please enter a number, or hit \"q\" to quit: ");

       while(scanf("%i", &input) == 1){

               printf("\nyou entered %i\n", input);

               if(oddEven == -1){

                       oddEven = input & 1;

               }else if(oddEven != (input & 1)){

                       oddEven = 2;

               }

       }

       switch(oddEven){

               case 0:

                       printf("The numbers are all even\n");

                       break;

               case 1:

                       printf("The numbers are all odd\n");

                       break;

               case 2:

                       printf("The numbers are both odd and even\n");

                       break;

               default:

                       // should never happen

                       printf("Something odd happened.");

       }

       return 0;

}

it is much more convenient for the consumer to order something online, rather than going to a store. it saves them time and money for them, especially if that item is not accessed easily.

storage maybe?

are there options?