Write a static method reOrder56(int[] nums) that return an array that contains exactly the same numbers as the given array, but has been reorderd so that every 5 is immediately followed by a 6. You may choose to move every other number with the exception of 5; You are not to move 5. The array contains the same number of 5's and 6's, every 5 has a number after it that is not a 5, and a 6 appears in the array before any 6.

Follows are the code to the given question:

static int[] reOrder56(int[] nums)//defining a static method reOrder56 that holds an array in parameter

{

   int x,y;//defining integer variables

   for(x=0;x<nums.length;x++)//using for loop that counts array  

   {

       if(nums[x]==5 && nums[x+1]!=6) //defining if block checks arry values

       {

           for(y=0;y<nums.length;y++)//use for loop to count array value again  

           {

               if(nums[y]==6 && nums[y-1]!=5)//defining if block checks arry values  

               {

                   nums[y] = nums[x+1];//swap the array element value

                   nums[x+1] = 6;//holing value in array

                   break;//break the condition

               }

           }

       }

   }

}

Explanation:

In this code, a static method "reOrder56" is declared that takes an integer array "nums" in its parameter, and inside the method, two integer variable "x, y" is defined, which is used in the nested loop.

In the first loop, it holds array values and uses the if block to check the array element value and define another loop to check the same condition, and this block, swap the value and holds the value in the array and breaks the condition.

well you didnt give us any options it looks like so im going to go with because cash cant be traced.