A Consider the following method definition. The method printAllCharacters is intended to print out every character in str, starting with the character at index 0. public static void printAllCharacters (String str) for (int x = 0; x< str. length(); x++) // Line 3 System. out. print(str. substring(x, x + 1)); The following statement is found in the same class as the printAllCharacters method. printAllCharacters ("ABCDEFG"); Which choice best describes the difference, if any, in the behavior of this statement that will result from changing x < str. length() to x <= str. length() in line 3 of the method? Α) The method call will print fewer characters than it did before the change because the loop will iterate fewer times.
B) The method call will print more characters than it did before the change because the loop will iterate more times.
C) The method call, which worked correctly before the change, will now cause a run-time error because it attempts to access a character at index 7 in a string whose last element is at index 6.
D) The method call, which worked correctly before the change, will now cause a run-time error because it attempts to access a character at index 8 in a string whose last element is at index 7.
E) The behavior of the code segment will remain unchanged.

Following are calculations to the given method.

Given:

Method printAllCharacters and printAllCharacters("ABCDEFG") are both required.

To find:

What happens if you change x <str.length() to x = str.length()?

Solution:

The first character is at index 0 while the last is at index 6. The loop should therefore be simplified:

for (int x = 0; x< str.length(); x++) means for (int x = 0; x< 7; x++)

when

for (int x = 0; x<=str.length(); x++) stands as for (int x = 0; x<= 7; x++).

Therefore, the final answer is "Option (c)"

Learn more:

link

(c) The method call, which worked correctly before the change, will now cause a run-time error because it attempts to access a character at index 7 in a string whose last element is at index 6.

Explanation:

Given

printAllCharacters method and printAllCharacters("ABCDEFG");

Required

What happens when  x < str.length() is changed to x <= str.length()

First, we need to understand that str.length()  gets the length of string "ABCDEFG"

There are 7 characters in "ABCDEFG".

So: str.length()  = 7

The first character is at index 0 and the last is at index 6

Next, we need to simplify the loop:

for (int x = 0; x< str.length(); x++) means for (int x = 0; x< 7; x++)

The above loop will iterate from the character at the 0 index to the character at the 6th index

while

for (int x = 0; x<=str.length(); x++) means for (int x = 0; x<=7; x++)

The above loop will iterate from the character at the 0 index to the character at the 7th index

Because there is no character at the 7th index, the loop will return an error

Hence: (c) is correct

answer; i believe the correct answer is (a) all trenches must have access/egress;

answer: internal fragmentation is the difference between the (fixed) size of a memory hole and the data within in that memory. for example, if a 1,024 byte block of memory holds 800 bytes of data, then the 224 bytes difference is considered lost to internal fragmentation.

external fragmentation occurs when the sum of memory fragments is large enough to satisfy a request, but the holes are non-contiguous and the request cannot be satisfied. this can occur when memory is dynamically allocated and freed.

explanation: