which of the following devices and and receive information from other device? a parallel port B serial port C video port d both a and b

Consider the following declarations (1, 2, 3, 5, 7)class bagtype{public: void set(string, double, double, double, double); void print() const; string getstyle() const; double getprice() const; void get(double, double, double, double); bagtype(); bagtype(string, double, double, double, double); private: string style: double l; double w; double h; double price; }; a.) write the definition of the number function set so that private members are set according to the parametersb.) write the definition of the member function print that prints the values of the data membersc.) write the definition of the default constructor of the class bagtype so that the private member variables are initialized to "", 0.0, 0.0, 0.0, 0.0, respectively d.) write a c++ statement that prints the value of the object newbag.e.) write a c++ statement that declares the object tempbag of type bagtype, and initialize the member variables of tempbag to "backpack", 15, 8, 20 and 49.99, respectively

All of these are true about using adhesive except: a. dissimilar materials can be joined. b. mixing tips are product and material specific. c. a specific application gun may be required. d. two-part adhesives are dispensed using two mixing tips

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words.size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words.size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }