Edhesive 4: Evens and Odds answer

n = int(input("How many numbers do you need to check? "))

even = 0

odd = 0

for i in range(n):

   n=int(input("Enter number: "))

   if (n%2 == 0):

        print(str(n)+" is an even number. ")

        even = even + 1

   else:

       print(str(n)+" is an odd number. ")

       odd = odd + 1

print("You entered "+str(even)+" even number(s).")

print("You entered "+str(odd)+" odd number(s).")

Explanation:

just copy and paste you will get 100 percent any questions comment below

some have built technology like spoofed call blockers into their networks, so there's nothing you would even have to install.

this happens because the number is known for scamming, they don't want it to me known as "scam likely." perhaps it's just a telemarketer. maybe it's an identity thief. it might even be a scam artist.  

either way, "scam likely" is probably not an old friend whose number you forgot that you saved. it's your wireless carrier's way of letting you know: answer at your own risk.

explanation:

to combat the seemingly rising epidemic of spam callers in the u.s., the nation's four major wireless carriers have been trying out new methods to reduce the number of unsolicited calls americans receive each day.

some have built technology like spoofed call blockers into their networks, so there's nothing you would even have to install.

hope this . mark me brainliest.