Write an application that stores the following nine integers in an array: 10, 15, 19, 23, 26, 29, 31, 34, 38. Display the integers from first to last, and then display the integers from last to first.

Following are the code to this question:

Program Explanation:

Program:

#include <iostream>// header file

using namespace std;

int main()//main method

{

int arr1[]= {10, 15, 19, 23, 26, 29, 31, 34, 38};//defining array of integer values

int i;//defining integer variable

cout<<" Array from first to last: ";//print message

for(i=0;i<9;i++)//use for loop to print array

{

cout<<arr1[i]<<" ";//print array value

}

cout<<"\n Array from last to first : ";//print message

for(i=9-1;i>=0;i--)//defining for loop to print array in reverse order

{

cout<<arr1[i]<<" ";//print array

}

return 0;

}

Output:

Array from first to last: 10 15 19 23 26 29 31 34 38  

Array from last to first : 38 34 31 29 26 23 19 15 10  

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solution:

the right option is a

to adding   a new row to a table we   have to do process last table cell and pressing tab.

this is the process to add new row in the cell:

* to add a row below the cell, click insert below in the rows and columns group.

thus this is the required right answer.