An anagram of a string is another string with the same characters in the same frequency, in any order. For example 'ab', 'bca, acb), 'bac', 'cba, 'cab' are all anagrams of the string 'abc'. Given two arrays of strings, for every string in one list, determine how many anagrams of it are in the other list. Write a function that receives dictionary and query, two string arrays. It should return an array of integers where each element i contains the number of anagrams of queryll that exist in dictionary.

from collections import Counter

def anagram(dictionary, query):

   newList =[]

   for element in dictionary:          

       for item in query:

           word = 0

           count = 0

           for i in [x for x in item]:

               if i in element:

                   count += 1

                   if count == len(item):

                       newList.append(item)

   ans = list()

   for point in Counter(newList).items():

       ans.append(point)

   print(ans)        

mylist = ['jack', 'run', 'contain', 'reserve','hack','mack', 'cantoneese', 'nurse']

setter = ['ack', 'nur', 'can', 'con', 'reeve', 'serve']

anagram(mylist, setter)

Explanation:

The Counter class is used to create a dictionary that counts the number of anagrams in the created list 'newList' and then the counter is looped through to append the items (tuple of key and value pairs) to the 'ans' list which is printed as output.

b.. i believe would be the right one sorry if im wrong.

a) click on any cells in the range of data

b) click the data

c) click sort& filter group, click sort

d) select the column to sort by and then select a sort order

e) select the next column to sort by and select the sort order

f) click ok