Write a function named minMax() that accepts three integers arguments from the keyboard and finds the smallest and largest integers. Include the function minMax() in a working program. Make sure your function is called from main().Test the function by passing various combinations of three integers to it.

public class Main

{

public static void main(String[] args) {

 minMax(1, 2, 3);

 minMax(100, 25, 33);

 minMax(11, 222, 37);

}

public static void minMax(int n1, int n2, int n3){

    int max, min;

    if(n1 >= n2 && n1 >= n3){

        max = n1;

    }

    else if(n2 >= n1 && n2 >= n3){

        max = n2;

    }

    else{

        max = n3;

    }

    if(n1 <= n2 && n1 <= n3){

        min = n1;

    }

    else if(n2 <= n1 && n2 <= n3){

        min = n2;

    }

    else{

        min = n3;

    }

    System.out.println("The max is " + max + "\nThe min is " + min);    

}

}

Explanation:

*The code is in Java.

Create a function named minMax() that takes three integers, n1, n2 and n3

Inside the function:

Declare the min and max

Check if n1 is greater than or equal to n2 and n3. If it is set it as max. If not, check if n2 is greater than or equal to n1 and n3. If it is set it as max. Otherwise, set n3 as max

Check if n1 is smaller than or equal to n2 and n3. If it is set it as min. If not, check if n2 is smaller than or equal to n1 and n3. If it is set it as min. Otherwise, set n3 as min

Print the max and min

Inside the main:

Call the minMax() with different combinations

i think the answer is b.