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Who likes Minecraft? UwU

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Computers and Technology, 22.06.2019 21:00
Simon says is a memory game where "simon" outputs a sequence of 10 characters (r, g, b, y) and the user must repeat the sequence. create a for loop that compares the two strings starting from index 0. for each match, add one point to userscore. upon a mismatch, exit the loop using a break statement. assume simonpattern and userpattern are always the same length. ex: the following patterns yield a userscore of 4: simonpattern: rrgbryybgy userpattern: rrgbbrybgy
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Computers and Technology, 24.06.2019 02:20
Peter is thinking of a number which isless than 50. the number has 9 factors.when he adds 4 to the number, itbecomes a multiple of 5. what is thenumber he is thinking of ?
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Computers and Technology, 24.06.2019 15:30
The idea that, for each pair of devices v and w, there’s a strict dichotomy between being “in range” or “out of range” is a simplified abstraction. more accurately, there’s a power decay function f (·) that specifies, for a pair of devices at distance δ, the signal strength f(δ) that they’ll be able to achieve on their wireless connection. (we’ll assume that f (δ) decreases with increasing δ.) we might want to build this into our notion of back-up sets as follows: among the k devices in the back-up set of v, there should be at least one that can be reached with very high signal strength, at least one other that can be reached with moderately high signal strength, and so forth. more concretely, we have values p1 ≥ p2 ≥ . . ≥ pk, so that if the back-up set for v consists of devices at distances d1≤d2≤≤dk,thenweshouldhavef(dj)≥pj foreachj. give an algorithm that determines whether it is possible to choose a back-up set for each device subject to this more detailed condition, still requiring that no device should appear in the back-up set of more than b other devices. again, the algorithm should output the back-up sets themselves, provided they can be found.\
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Computers and Technology, 25.06.2019 08:20
In the following table, column a is column b is and column c is
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