In Chapter 4, we developed an algorithm for converting from binary to decimal. You can generalize this algorithm to work for a representation in any base. Instead of using a power of 2, you will write a program that converts any base between 2 and 16. Recall that for numbers 10 - 15 we use letters A - F. In convert. py, define a function named repToDecimal that expects two arguments, a string, and an integer. The second argument should be the base. For example, repToDecimal("10", 8) returns 8, whereas repToDecimal("10", 16) returns 16. The function should use a lookup table to find the value of any digit. Make sure that this table (it is actually a dictionary) is initialized before the function is defined. For its keys, use the 10 decimal digits (all strings) and the letters A . . . F (all uppercase). The value stored with each key should be the integer that the digit represents. (The letter A associates with the integer value 10, and so on.) The main loop of the function should convert each digit to uppercase, look up its value in the table, and use this value in the computation. A main function that tests the conversion function with numbers in several bases has been provided.

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words.size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words.size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }