Write a function that takes a string and return the back half of the string. If the string has an odd number of characters, include the extra character. Your solution should also work if given and empty string. Examples: back_half('abba') should return 'ba' back_half('abcba') should return 'cba'

Written in Python

def back_half(inputstring):

    outputstring = ""

    lent = len(inputstring)

    if lent == 0:

         outputstring ="Empty String"

    elif lent%2 == 0:

         begin = lent/2

         for i in range(int(begin),lent):

              outputstring = outputstring + inputstring[i]

    else:

         begin = (lent+1)/2

         for i in range(int(begin-1),lent):

              outputstring = outputstring + inputstring[i]

    return outputstring

Explanation:

This line defines the function

def back_half(inputstring):

This line initializes outputstring to an empty string

    outputstring = ""

This calculates the length of the input string

    lent = len(inputstring)

This checks if the length of inputstring is 0. If yes, the function returns empty string

    if lent == 0:

         outputstring ="Empty String"

This checks if the length of inputstring is even.

    elif lent%2 == 0:

         begin = lent/2 This line gets the beginning of the half string

         for i in range(int(begin),lent):

              outputstring = outputstring + inputstring[i] This generates the half string

    else: This checks for odd length

         begin = (lent+1)/2 This line gets the beginning of the half string

         for i in range(int(begin-1),lent):

              outputstring = outputstring + inputstring[i] This generates the half string

    return outputstring This returns the outputstring

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