Write an assignment statement for the following mathematical equation: y = (1/3)x + (x/4) + 2x Keep x as an integer. Use an expression that matches the equation's right side as closely as possible. If the input is -1, the output is -2.583333333333333. Hints: Don't rearrange the equation or try to simplify it. If both operands of division (or other operators) are integers, integer division is performed, which rounds down; so for example 1/2 is 0. So make at least one operand a floating-point type, as in 1.0/2, or 1.0/2.0, to cause floating-point division.

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

   Scanner input = new Scanner(System.in);

   int x = input.nextInt();

   double y = (1.0/3) * x + (x/4.0) + (2*x);

   System.out.println(y);

}

}

Explanation:

*The code is in Java.

Create a Scanner object to get an input from the user

Get the input using the Scanner object and assign the value to the x

Initialize y as double (Since the output has decimal places, it needs to be initialized as double) and convert the given equation to the Java convention.

To get exact result from 1/3, you need to make at least one operand a floating-point type

To get exact result from x/4, you need to make at least one operand a floating-point type.

To multiply 1/3 and x, you need to use "*" between them

To multiply 2 and x, you need to use "*" between them

Finally, print the y

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