Write a function index(elem, seq) that takes as inputs an element elem and a sequence seq and returns the index of the first occurrence of elem in seq. The sequence seq can be either a list or a string. If seq is a string, elem will be a single-character string; if seq is a list, elem can be any value. If elem is not an element of seq, the function should return the length of the sequence. Dont forget that the index of the first element in a sequence is 0. Here are some examples: >>> index(5, [4, 10, 5, 3, 7, 5]) solution

def index(elem, seq):

   for i in range(len(seq)):

       if elem == seq[i]:

           return i

   return len(seq)

print(index(5, [4, 10, 8, 5, 3, 5]))

Explanation:

Create a function named index that takes elem and seq as parameters

Create a for loop that iterates through the seq. If elem is equal to the item in the seq, return the i, index of the item.

If the elem is not found in the seq, this means nothing will be returned in the loop, just return the length of the seq, len(seq)

Call the function with given parameters and print the result

Note: Since 5 is in the list in the example, the index of the 5 which is 3 will be returned

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explanation:

its b

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