(a) How many locations of memory can you address with 12-bit memory address? (b) How many bits are required to address a 2-Mega-location memory, i. e, what should the length of the memory address be in order to access a 2M memory? (c) Assume intArray is an integer array with 20 elements stored in memory and its starting memory address is in $s2. What is the memory address for element intArray [10]? (d) Assume charArray is a character array with 20 elements stored in memory and its starting memory address is in $t5. What is the memory address for element charArray[5]?

Follows are the solution to this question:

Explanation:

In point a:

Let,

The address of 1-bit  memory  to add in 2 location:

The address of 2-bit  memory to add in 4 location:

similarly,

Complete 'n'-bit memory address' location number is = Here, 12-bit memory address, i.e. n = 12, hence the numeral. of the addressable locations of the memory:

In point b:

So,

The memory position for '' could be 'n' m bits'  

It can use bits to address the memory location of 21.  

That is to say, the 2-mega-location memory needs '21' bits.  

Memory Length = 21 bit Address

In point c:

element array addresses are given by:

1 term is 4 bytes in 'MIPS,' that is:

In point d:

When MIPS is 1 word which equals to 32 bit :

In Unicode, its value is = 2 byte

In ASCII code its value is = 1 byte

both sizes are  < 4 byte

Calculating address:

the answer would be d. online forums.

hope it