Merge arrays A and B into array C using merge sort algorithm. Give final sorted numbers of C using colored numbers without showing intermediate steps. For example, your answer can be [1, 3, 3, 5, 7, 7, 9, 9, 13, 25] or [1, 3, 3, 5, 7, 7, 9,9, 13, 25), or another variation. void merge(int all, int aux[], int lo, int mid, int hi) / for (int k = lo; k<= hi; k++) aux [k] a[k]; int i lo, j = mid+1; for (int k lo; k<-hi; k++) if (i > mid) ak) else if (1 > hi) a[k] else if (small (aux(j), aux[1])) a[k] else ak aux[j++); aux (i++); aux [j++); /*++ aux (i++]; 1 j++

Explanation:

Given code:-

#include<iostream>

using namespace std; //namespace

#define RED "\033[31m" /* Red */

#define BLUE "\033[34m" /* Blue */ //color definition

#define WHITE "\033[37m" /* White */

void mergeArrays(int arr1[], int arr2[], int n1, int n2, int arr3[])

//merger sort

{

int i = 0, j = 0, k = 0;

while (i<n1 && j <n2) //iterate over both array

{

if (arr1[i] < arr2[j]) //iff array 1 element is larger

{

arr3[k] = arr1[i]; //assign to a3

k++;

i++;

}

else

{

arr3[k] = arr2[j]; //else assign array 2 to a3

j++;

k++;

}

}

//say the array turns out to br of different sizes

//let us copy the remaining elemnt to array 3

while (i < n1)

{

arr3[k] = arr1[i];

i++;

k++;

}

while (j < n2)

{

arr3[k] = arr2[j];

k++;

j++;

}

}

int main(){

int A[4] = {3,5,7,9}; //array 1 assignment

int a_size = 4;

int b_size = 6;

int B[6] = {1,3,7,9,13,25}; //array 2 assignment

int C[10]; //array 3 declearation

int a_count = 0;

int b_count = 0; //counter for both array index

mergeArrays(A,B,a_size,b_size,C); //merger function applied;

cout<<WHITE<<"A: ";

for(int i = 0; i<4; i++){

cout<<RED<<A[i]<<" ";

}

cout<<endl<<WHITE<<"B: ";

for(int i = 0; i<6; i++){

cout<<BLUE<<B[i]<<" ";

}

cout<<endl<<WHITE<<"C: ";

for(int i = 0; i<10; i++){ //iterate over C

if(C[i] == A[a_count] && a_count < a_size){

cout<<RED<<C[i]<<" ";

// if element is common in array 1 print in red

a_count++;

}

else if (C[i] == B[b_count] && b_count < b_size){

//say element was similar in array 2,  print in blue

cout<<BLUE<<C[i]<<" ";

b_count++;

}

}

cout<<endl;

}

answer; i believe that the correct answer is a ( check first..good luck