Write code to complete DoublePennies()'s base case. Sample output for below program:Number of pennies after 10 days: 1024#include using namespace std;// Returns number of pennies if pennies are doubled numDays timeslong long DoublePennies(long long numPennies, int numDays){long long totalPennies = 0;/* Your solution goes here */else {totalPennies = DoublePennies((numPennies * 2), numDays - 1);}return totalPennies;}// Program computes pennies if you have 1 penny today,// 2 pennies after one day, 4 after two days, and so onint main() {long long startingPennies = 0;int userDays = 0;startingPennies = 1;userDays = 10;cout << "Number of pennies after " << userDays << " days: "<< DoublePennies(startingPennies, userDays) << endl;return 0;}