Assign max_sum with the greater of num_a and num_b, PLUS the greater of num_y and num_z. Use just one statement. Hint: Call find_max() twice in an expression. Sample output with inputs: 5.0 10.0 3.0 7.0
max_sum is: 17.0
1 det find_max(num_1, num_2):
2 max_val = 0.0
3
4 if (num_1 > num_2): # if num1 is greater than num2,
5 max_val = num_1 # then num1 is the maxVal.
6 else: # Otherwise,
7 max_val = num_2 # num2 is the maxVal
8 return max_val
9
10 max_sum = 0.0
11
12 num_a = float(input)
13 num_b = float(input)
14 num_y = float(input)
15 num_z = float(input)
16
17"" Your solution goes here
18
19 print('max_sum is:', max_sum)

def find_max(num_1, num_2):

   max_val = 0.0

   if (num_1 > num_2): # if num1 is greater than num2,

       max_val = num_1 # then num1 is the maxVal.

   else: # Otherwise,

       max_val = num_2 # num2 is the maxVal

   return max_val

max_sum = 0.0

num_a = float(input())

num_b = float(input())

num_y = float(input())

num_z = float(input())

max_sum = find_max(num_a, num_b) + find_max(num_y, num_z)

print('max_sum is:', max_sum)

Explanation:

I added the missing part. Also, you forgot the put parentheses. I highlighted all.

To find the max_sum, you need to call the find_max twice and sum the result of these. In the first call, use the parameters num_a and num_b (This will give you greater among them). In the second call, use the parameters num_y and num_z (This will again give you greater among them)

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