Soft tissue follows an exponential deformation behavior in uniaxial tension while it is in the physiologic or normal range of elongation. This can be expressed as θ=E0/a(eae-1)where σ stress, strain, and Eo and a are material constants that are determined experimentally. To evaluate the two material constants, the above equation is differentiated with respect to e to produce Eq.2) 1. Starting from (eq.1), establish the fundamental relationship for soft tissue (eq 2) dθ/ de=Eo+aθ To evaluate E, and a, stress-strain data is plotted asa-versus σ and the intercept and slope of this plot are the two material constants In the following table, the stress-strain data for heart chordae tendineae (small tendons used to hold heart valves closed during contraction of the heart muscle); this data is from loading the tissue, while deferent curves are produced on unloading. 207.8 216.6 296 383 471 691 954 1349 1744 2227 2798 3500 4378 153 204 255 306 357 408 459 510 561 612 663 714 765 2. Calculate the derivativeda using the following finite differences a. Three point forward difference for the first point b. Three point backward difference for the last point c. Two point central difference for the internal points 3, plot the calculated data-versus σ de and d. Perform a (linear) least square regression analysis and determine the values of E. Use the calculated values of Eo and a from the previous question, and plot the stress versus strain data points (table.1) along with the analytic curve expressed by Eq.1. This will indicate how well the analytic curve matches the data. (Label the axes; add a title and a legend).