C program, Assign negativeCntr with the number of negative values in the linked list, including the list head. #include
#include
typedef struct IntNode_struct {
int dataVal;
struct IntNode_struct* nextNodePtr;
} IntNode;
// Constructor
void IntNode_Create(IntNode* thisNode, int dataInit, IntNode* nextLoc) {
thisNode->dataVal = dataInit;
thisNode->nextNodePtr = nextLoc;
}
/* Insert newNode after node.
Before: thisNode -- next
After: thisNode -- newNode -- next
*/
void IntNode_InsertAfter(IntNode* thisNode, IntNode* newNode) {
IntNode* tmpNext = NULL;
tmpNext = thisNode->nextNodePtr; // Remember next
thisNode->nextNodePtr = newNode; // this -- new -- ?
newNode->nextNodePtr = tmpNext; // this -- new -- next
}
// Grab location pointed by nextNodePtr
IntNode* IntNode_GetNext(IntNode* thisNode) {
return thisNode->nextNodePtr;
}
int IntNode_GetDataVal(IntNode* thisNode) {
return thisNode->dataVal;
}
int main(void) {
IntNode* headObj = NULL; // Create intNode objects
IntNode* currObj = NULL;
IntNode* lastObj = NULL;
int i; // Loop index
int negativeCntr;
negativeCntr = 0;
headObj = (IntNode*)malloc(sizeof(IntNode)); // Front of nodes list
IntNode_Create(headObj, -1, NULL);
lastObj = headObj;
for (i = 0; i < 10; ++i) { // Append 10 rand nums
currObj = (IntNode*)malloc(sizeof(IntNode));< br /> IntNode_Create(currObj, (rand() % 21) - 10, NULL);
IntNode_InsertAfter(lastObj, currObj); // Append curr
lastObj = currObj; // Curr is the new last item
}
currObj = headObj; // Print the list
while (currObj != NULL) {
printf("%d, ", IntNode_GetDataVal(currObj));
currObj = IntNode_GetNext(currObj);
}
printf("\n");
currObj = headObj; // Count number of negative numbers
while (currObj != NULL) {
/* Your solution goes here */
currObj = IntNode_GetNext(currObj);
}
printf("Number of negatives: %d\n", negativeCntr);
return 0;
}