Function Name: d2x Parameters: int, int Returns: string Description: Write function, d2x, that takes as input a nonnegative integer v (in the standard decimal representation) and an integer x between 2 and 9 and returns a string of digits that represents the base-x representation of v. To convert a value, v from base-10 to base-x, v is divided by x successively until the quotient of v divided by x is 0. On each successive division, the remainder is the new most significant digit in your answer. For the function call, d2x(10, 2), should return '1010':

I am writing a Python program. Let me know if you want the program in some other programming language.

#definition of function d2x which takes two parameters v: which is a non #negative integer and x which is an integer between 2 and 9. this method #returns string of digits that represents the base-x representation of v

def d2x(v,x):

   remainder = v%x  

   if v<=1:

       return str(v)

   else:

       return str(d2x(v//x,x)) + str(remainder)

v= int(input("Enter a non negative integer: "))

x= int(input("Enter an integer between 2 and 9: "))

print(d2x(v,x))

Explanation:

I will explain the code line by line.

def d2x(v,x) This is the definition of function d2x which takes two parameters v: which is a non negative integer and x which is an integer between 2 and 9. This method returns string of digits that represents the base-x representation of v.

Now lets take an example to understand the working of this function.

Suppose the value of v = 10 and x = 2.

remainder = v%x  takes the mod of v and x which returns the remainder of the division of v by x. So v%x = 10 % 2 = 0. So remainder = 0.

if v<=1 This if condition checks if the value of v is less than or equal to 1. This is false because v=10 and 10 is greater than 1. If v is 1 or less than return str(v)  will return the value of v as it is i.e. 10.

Since the IF condition is false so the else part will execute which has the following statement: return str(d2x(v//x,x)) + str(remainder)

This calls the d2x function recursively. Here v is divided by x successively until the quotient of v divided by x is 0. On each successive division, the remainder is the new most significant digit. In v//x, the double slash is called floor division or integer division which we use as both v and x are integers. So using recursion the above statement becomes:

str(d2x(v//x,x)) + str(remainder)

str(d2x(10//2,2) + str(0)

d2x(5,2) + (0)

Now d2x will again be called recursively to perform the division and this successive division continues until quotient of v divided by x is 0. Here str() method is used returns the result in the form of string.  So v%x is the number which is added to the end of resultant number. v//x is the recursive portion which keeps using the answer of the previous binary number. This means 10 in base 2 calls convert(5,2), then adds 0 at the end. So when v//x=5 and v%x=0 So the answer is 1010.

At the end v= int(input("Enter a non negative integer: "))

x= int(input("Enter an integer between 2 and 9: "))  these two statement wills take integer input from user and print(d2x(v,x)) calls d2x method and print the result.

a) click on any cells in the range of data

b) click the data

c) click sort& filter group, click sort

d) select the column to sort by and then select a sort order

e) select the next column to sort by and select the sort order

f) click ok