Write a function PrintShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N: Lather and rinse." numCycles times, where N is the cycle number, followed by "Done.". End with a newline. Example output for numCycles = 2: 1: Lather and rinse.
2: Lather and rinse.
Done.
Hint: Define and use a loop variable.
Sample program:
#include
using namespace std;

int main() {
PrintShampooInstructions(2);
return 0;
}

public static void PrintShampooInstructions(int numberOfCycles){

       if (numberOfCycles<1){

           System.out.println("Too Few");

       }

       else if(numberOfCycles>4){

           System.out.println("Too many");

       }

       else

           for(int i = 1; i<=numberOfCycles; i++){

               System.out.println(i +": Lather and rinse");

           }

       System.out.println("Done");

   }

Explanation:

I have used Java Programming language to solve this

Use if...elseif and else statement to determine and print "Too Few" or "Too Many".

If within range use a for loop to print the number of times

#In Python

def shampoo_instructions(num_cycles):

   if num_cycles < 1: ///

       print ('Too few.') ///

   elif num_cycles > 4:

       print ('Too many.')

   else:

       i = 0

       while i<num_cycles:

           print (i+1,": Lather and rinse.")

           i = i + 1

       print('Done.')

user_cycles = int(input())

shampoo_instructions(user_cycles)

Explanation:

def shampoo_instructions(num_cycles): #def function with loop

   if num_cycles < 1:  #using 1st if statement

       print('Too few.')

   elif num_cycles > 4:

       print ('Too many.')

   else:

       i = 0

       while i<num_cycles:

           print (i+1,": Lather and rinse.")

           i = i + 1

       print('Done.')

user_cycles = int(input())

shampoo_instructions(user_cycles)

the anwser is ethier d or e

answer///router;