The IBM 370 mainframe computer was introduced in 1970. The 370 Model 145 could hold up to 524,288 bytes of data (512 Kbytes). It cost $1,783,000.00 to buy (or $37,330/month to rent). A notebook computer today holds 16 Gbytes of memory and costs $2,500 to buy. If you assume that 100% of the price is just the memory, for both computers: • how much did 1 Kbyte of memory in the IBM computer cost?
• how much does 1 Kbyte of memory in the laptop cost?
• how many times cheaper is the memory in the laptop than memory in the mainframe?
• what factor is today’s computer cheaper than the IBM 370?

a) $3482.4 per Kbyte

b) $0.000149 per Kbyte

c) The laptop is 23369991 times cheaper than the mainframe computer

d) Today's computer is 23369991 times cheaper than IBM 370

Explanation:

a) The 370 Model 145 could hold up to 524,288 bytes of data

one Kb = 1024 bytes, therefore  524,288 bytes =  524288/1024 Kbytes= 512 Kbytes. It cost $1,783,000.00 to buy (or $37,330/month to rent).

Since 100% of the price is just the memory

Cost per 1 Kb = cost of computer / memory

Cost per 1 Kb =  $1,783,000 / 512 Kb = $3482.4 per Kbyte

b)   A notebook computer today holds 16 Gbytes of memory

one Kb = 1024 bytes, 1024 Kb = 1 Mbyte, 1024 Mbytes = 1 Gbyte.

Therefore 16 Gbytes =  (16 * 1024 * 1024) Kbytes = 16777216 Kbytes. It cost $2500 to buy

Since 100% of the price is just the memory

Cost per 1 Kb = cost of computer / memory

Cost per 1 Kb =  $2500 /16777216 Kb = $0.000149 per Kbyte

c) Cost per 1 Kb for mainframe/ Cost per 1 Kb for laptop = $3482.4 per Kbyte / $0.000149 per Kbyte = 23369991

The laptop is 23369991 times cheaper than the mainframe computer

d) Today's computer is 23369991 times cheaper than IBM 370

well you didnt give us any options it looks like so im going to go with because cash cant be traced.