3. Write a program that inputs 4 hexadecimal digits as strings (example 7F), converts the string digits to a long – use strtol(input string,&ptr, base) to do the conversion. Just declare ptr as a char ptr, don’t worry about what it does. Copy each converted number [ a long] into unsigned char’s [like the variable num1 below – hint: cast a long variable into the unsigned char’s] before performing the following logical operations on them (parenthesis might help, since things should be executed from left to right): result=num1 and num2 or num 3 exclusive or num4 print out result in capital hex (15 points)

#include <stdio.h>

#include <stdlib.h>

int main()

{

char num1[20],num2[20],num3[20],num4[20];

//Checks where the conversion of string to long stops and is required by strtol

char *ptr;

//Stores the converted number string into long.

long result_num1,result_num2,result_num3,result_num4;

//Prompt to enter all the four hexadecimal numbers.

printf("Enter the first hexadecimal number: ");

scanf("%s",num1);

printf("Enter the second hexadecimal number: ");

scanf("%s",num2);

printf("Enter the third hexadecimal number: ");

scanf("%s",num3);

printf("Enter the fourth hexadecimal number: ");

scanf("%s",num4);

//Converting the hexadecimal numbers into long using strtol() function with base 16 for hexadecimal.

result_num1 = strtol(num1,&ptr,16);

result_num2 = strtol(num2,&ptr,16);

result_num3 = strtol(num3,&ptr,16);

result_num4 = strtol(num4,&ptr,16);

//Casting the long to unsigned chars.

unsigned char numb1 = (unsigned char)result_num1;

unsigned char numb2 = (unsigned char)result_num2;

unsigned char numb3 = (unsigned char)result_num3;

unsigned char numb4 = (unsigned char)result_num4;

//Applying the boolean operation on unsigned chars and storing the resultant value in result.

unsigned char result = ((numb1&numb2)|numb3)^numb4;

//Printing the result in capital hex ("%X" take care of this).

printf("%X",result);

return 0;

}

Code OUTPUT

Enter the first hexadecimal number: 1 Enter the second hexadecimal number:2

Enter the third hexadecimal number: 3 Enter the fourth hexadecimal number: 4 Resultant Value: 7 Process returned o (0×0) execution time : 3.076 s

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