Write a generator function named count_seq that doesn't take any parameters and generates a sequence that starts like this: 2, 12, 1112, 3112, 132112, 1113122112, 311311222112, 13211321322112, ... To get a term of the sequence, enumerate how many there are of each digit (in a row) in the previous term. For example, the first term is "one 2", which gives us the second term "12". That term is "one 1" followed by "one 2", which gives us the third term "1112". That term is "three 1" followed by "one 2", or 3112. Etc. Your generator function won't just go up to some limit - it will keep going indefinitely. It may need to treat the first one or two terms as special cases, which is fine. It should yield the terms of the sequence as strings, rather than numeric values, for example "1112" instead of 1112. Your file must be named: count_seq. py

Which of the following “invisible” marks represents an inserted tab?

What a backup plan that you have created in a event you encounter a situation

Given a link with a maximum transmission rate of 32.8 mbps. only two computers, x and y, wish to transmit starting at time t = 0 seconds. computer x sends filex (4 mib) and computer y sends filey (244 kib), both starting at time t = 0. statistical multiplexing is used, with details as follows packet payload size = 1000 bytes packet header size = 24 bytes (overhead) ignore processing and queueing delays assume partial packets (packets consisting of less than 1000 bytes of data) are padded so that they are the same size as full packets. assume continuous alternating-packet transmission. computer x gets the transmission medium first. at what time (t = ? ) would filey finish transmitting? give answer in milliseconds, without units, and round to one decimal places (e.g. for an answer of 0.013777 seconds you would enter "13.8" without the quotes)