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In deadlock avoidance using banker’s algorithm, what would be the consequence(s) of: (i) a process declaring its maximum need as maximum possible for each resource. in other words, if a resource a has 5 instances, then each process declares its maximum need as 5. (ii) a process declaring its minimum needs as maximum needs. for example, a process may need 2-5 instances of resource a. but it declares its maximum need as 2.
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Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput.find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }
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Computers and Technology, 24.06.2019 15:30
The idea that, for each pair of devices v and w, there’s a strict dichotomy between being “in range” or “out of range” is a simplified abstraction. more accurately, there’s a power decay function f (·) that specifies, for a pair of devices at distance δ, the signal strength f(δ) that they’ll be able to achieve on their wireless connection. (we’ll assume that f (δ) decreases with increasing δ.) we might want to build this into our notion of back-up sets as follows: among the k devices in the back-up set of v, there should be at least one that can be reached with very high signal strength, at least one other that can be reached with moderately high signal strength, and so forth. more concretely, we have values p1 ≥ p2 ≥ . . ≥ pk, so that if the back-up set for v consists of devices at distances d1≤d2≤≤dk,thenweshouldhavef(dj)≥pj foreachj. give an algorithm that determines whether it is possible to choose a back-up set for each device subject to this more detailed condition, still requiring that no device should appear in the back-up set of more than b other devices. again, the algorithm should output the back-up sets themselves, provided they can be found.\
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