Given dictionaries, d1 and d2, create a new dictionary with the following property: for each entry (a, b) in d1, if a is not a key of d2 (i. e., not a in d2) then add (a, b) to the new dictionary for each entry (a, b) in d2, if a is not a key of d1 (i. e., not a in d1) then add (a, b) to the new dictionary For example, if d1 is {2:3, 8:19, 6:4, 5:12} and d2 is {2:5, 4:3, 3:9}, then the new dictionary should be {8:19, 6:4, 5:12, 4:3, 3:9} Associate the new dictionary with the variable d3

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Explanation:

# python code

import sys

import readline

from sys import stdin

import random

d1 = {2:3, 8:19, 6:4, 5:12}

d2 = {2:5, 4:3, 3:9}

d3 = {}

#for each entry (a, b) in d1

for i,v in d1.items():

  # if a is not a key of d2

  if i not in d2.keys():

      # add (a,b) to the new dictionary

      d3[i] = v

# for each entry (a, b) in d2

for i,v in d2.items():

  # if a is not a key of d1

  if i not in d1.keys():

      #add (a,b) to the new dictionary

      d3[i] = v

print "d3: ", d3

#output: d3: {8: 19, 3: 9, 4: 3, 5: 12, 6: 4}

Kindly check the Screenshot below.

the formula for work is

f*d

therefore work=2.0n*3.0=6n*m

i prefer xbox one. : )