In particular, create a calculator such that: - if `operation` has the value 'add', then `answer` gets set as the sum of `num1` and `num2` - elif `operation` has the value 'subtract', then `answer` gets set as the difference of `num2` from `num1` - elif `operation` has the value 'multiply', then `answer` gets set as the product of `num1` and `num2` - elif `operation` has the value 'divide', then `answer` gets set as the quotient of `num1` divided by `num2` - else `answer` gets set as the value 'not a thing'

Atool that matches persoal skills qualities interests and talets to a career is called a

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i.e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }

My has been slow anyone else’s ?