Computers and Technology, 14.04.2020 19:38 prince96
Void fun1(void); /* prototype */ void fun2(void); /* prototype */ void fun3(void); /* prototype */ void main() { int a, b, c; . . . } void fun1(void) { int b, c, d; . . . } void fun2(void) { int c, d, e; . . . } void fun3(void) { int d, e, f; . . . } Given the following calling sequences and assuming that dynamic scoping is used, what variables are visible during execution of the last function called? Include with each visible variable the name of the function in which it was defined. a. main calls fun1; fun1 calls fun2; fun2 calls fun3. b. main calls fun1; fun1 calls fun3. c. main calls fun2; fun2 calls fun3; fun3 calls fun1. d. main calls fun3; fun3 calls fun1. e. main calls fun1; fun1 calls fun3; fun3 calls fun2. f. main calls fun3; fun3 calls fun2; fun2 calls fun1.
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Computers and Technology, 22.06.2019 21:00
Write a method so that the main() code below can be replaced by the simpler code that calls method original main(): public class calcmiles { public static void main(string [] args) { double milesperhour; double minutestraveled; double hourstraveled; double milestraveled; milesprhour = scnr.nextdouble(); minutestraveled = scnr.nextdouble(); hourstraveled = minutestraveled / 60.0; milestraveled = hourstraveled * milesperhour; system.out.println("miles: " + milestraveled); } }
Answers: 2
Computers and Technology, 23.06.2019 03:30
Hashtags serve to identify the topic of a given tweet true false
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Computers and Technology, 23.06.2019 04:31
Which of the following is not a way in which trees benefit the environment? a. they remove a significant amount of carbon dioxide from the atmosphere. b. they remove a significant amount of oxygen from the atmosphere. c. their roots hold soil in place, reducing rates of erosion. d. they remove ozone and particulates from the atmosphere. select the best answer from the choices provided a b c d
Answers: 1
Computers and Technology, 23.06.2019 06:20
What is a point-in-time measurement of system performance?
Answers: 3
Void fun1(void); /* prototype */ void fun2(void); /* prototype */ void fun3(void); /* prototype */ v...
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