Write a program that allows users to enter a series of numbers and displays frequency of each number. Implement the following: 1. The user can enter a maximum of 20 numbers or enter-1 to end the series 2. Only numbers between 0..9 is allowed (or -1 ); if the user enters a number outside the valid input, inform the user and ask them to enter a valid number 3. Display the frequency of each number in the output. If the user input is 0,0,1,2,2,4,5,8,8,8,9,9, -1 the output will be:

zero = one = two = three = four = five = six = seven = eight = nine = 0

while True:

   number = int(input("Enter a number: "))

   if number == -1:

       break

   elif 0 <= number <= 9:

       if number == 0:

         zero += 1

       elif number == 1:

         one += 1

       elif number == 2:

         two += 1

       elif number == 3:

         three += 1

       elif number == 4:

         four += 1

       elif number == 5:

         five += 1

       elif number == 6:

         six += 1

       elif number == 7:

         seven += 1

       elif number == 8:

         eight += 1

       elif number == 9:

         nine += 1

   else:

       print("Invalid input!")

print("0 -> " + str(zero) + "," + " 1 -> " + str(one) + "," + " 2 -> " + str(two) + "," + " 3 -> " + str(three))

print("4 -> " + str(four) + "," + " 5 -> " + str(five) + "," + " 6 -> " + str(six) + "," + " 7 -> " + str(seven))

print("8 -> " + str(eight) + "," + " 9 -> " + str(nine))

Explanation:

Initialize the variables to hold the count for each digit

Initialize a while loop that iterates until a specified condition is reached

Inside the loop:

Get a number from the user and check

If the number is -1, stop the loop

If it is between 0 to 9, increase corresponding count value by 1

If it is out of range, print an error message

When the loop is done, print each count variable

which of the following is not an effect of technology on farming?

the correct answer is: it makes farmers perform more tasks by hand for apex.