A mini-app that provides information such as the time, date, news headlines, or weather. Can give you a quick look at what hardware and software is installed The initial screen that is displayed when an OS has a GUI interface loaded A tool that lists errors and issues that need attention Creates a folder with a .zip extension A directory that is housed inside another a directory A utility that can be used to solve a failed network connection A Microsoft online storage service Small programs stored on the hard drive that tell the computer how to communicate with a specific hardware device Found on the left side of the Windows Explorer or Computer window a. gadget b. System window c. Desktop d. Action Center e. Compressed folder f. Child directories g. Network and Sharing center h. OneDrive i. Device drivers j. Navigation pane

Ou listened to a song on your computer. did you use hardware or software?

What a backup plan that you have created in a event you encounter a situation

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words.size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words.size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }