Write a recursive method called repeat that accepts a string s and an integer n as parameters and that returns s concatenated together n times. For example, repeat("hello", 3) returns "hellohellohello", and repeat("ok", 1) returns "ok", and repeat("bye", 0) returns "". String concatenation is an expensive operation, so for an added challenge try to solve this problem while performing fewer than n concatenations.

The  recursive method called repeat in this exercise will be implemented using the Kotlin programming language

fun repeat (s:String, n: Int ) {

repeat(n) {

   println("s")

}

}

In the above code, the Kotlin repeat  inline function was used to archive the multiple output of the desired string, here is a documentation of how the repeat keyword/function works inline

fun repeat(times: Int, action: (Int) -> Unit)

//Executes the given function action specified number of times.

Learn more about Recursive methods:

link

public static String repeat(String text, int repeatCount) {

   if(repeatCount < 0) {

       throw new IllegalArgumentException("repeat count should be either 0 or a positive value");

   }

   if(repeatCount == 0) {

       return "";

   } else {

       return text + repeat(text, repeatCount-1);

   }

}

Explanation:

Here repeatCount is an int value.

at first we will check if repeatCount is non negative number and if it is code will throw exception.

If the value is 0 then we will return ""

If the value is >0 then recursive function is called again untill the repeatCount value is 0.

i think so.

by: nicholas