Create a cell array containing the same data as above (Do not use built-in functions such as cell2array, struct2cell, etc. but use direct definition). The first row of the array will contain Mercury, 35.98, 3031 etc.

clc;

clear all;

disp('Creating the cell arr of required values')

arr = { 'Alejandro', 11, {3 5 7 9}, {0 0}, 'UCSD2016';...

{8 6 4 2 0 -2}, pi, 'Stephanie', {1 0}, {'(858) 273-0173'} }

disp('First row second column')

exp1 = arr(1 : 2, 2)

disp('Third element of 2nd row 1st column')

exp2 = arr{2, 1}(1,3)

disp('Deleting last 2 elements of 1st row 2nd column')

arr{1, 3}(3:4) = []

disp('log of 2nd row 2nd column')

arr{2, 2} = log(arr{2, 2})

disp('Swapping 1st row 1st column with 2nd row 3rd column')

temp = arr{2, 3};

arr{2, 3} = arr{1, 1}

arr{1, 1} = temp

disp('Deleting 2nd row 1st column elements')

arr{2, 1}(1:6)=[]

disp('Deleting third column')

arr(:,3) = []

answei'm sorry. i am having trouble understanding what you're asking? i'm willing to but tell me what you mean : )

explanation: