Your friend Margo is considering what type of display to purchase with her new desktop computer and she asks you for advice. You tell Margo that most monitors today have a small footprint. What does this mean?
a. They use little power.
b. They do not have a wide range of wireless connectivity.
c. They can be used with multiple devices simultaneously.
d. They do not take up much desk space.

Problems: 1. using textbooks, reference books, and internet as your source of research, draw the following microprocessor microarchitectures i. intel 8086 ii. motorola 68000 i atmel atmega32 iv. mips single cycle v. arm cortex-m3 write an hdl module for a hexadecimal seven-segment display decoder. the input is 4-bit binary representing a hex number (0-f), and the output is 8-bit seven segment display bits (a-h). thus, the decoder must handle the digits 10 - 15 to display a-f respectively, in addition to 0-9 numbers. 2. design a 4-bit left and right rotator (both outputs). first sketch schematic diagrams of your design. then implement your design using hdl coding. 3. 4. design a modified priority encoder that receives an 8-bit input, a7: 0 and produces a 3-bit output, y2o. y indicates the most significant bit of the input that is true. y should be 0 if none of the inputs are true. give a simplified boolean equation, sketch a schematic, and write an hdl code. 5.write an 8: 1 multiplexer module called mux8 with selection inputs s, data input d, and data output y. data input (d) and data output (v) are 32-bit wide

The most accurate readings that you can take on an analog vom are when the meter's pointer is at the a. center scale. b. extreme right. c. near right. d. extreme left.

When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?