"In a TCP connection, suppose that loss occurs whenever the window size of a connection hits W. Also suppose that the RTT is constant. Then the approximate average transmission rate is:"

The approximate average transmission rate is (.75*W*MSS)/RTT.

Explanation:

In TCP, the acknowledgement number that a host puts in a segment is the sequence number of the next byte the host is expecting from the sender.

If a connection transmits W segments of size MSS bytes every RTT seconds, then the connection's throughput, or transmission rate, is ( W*MSS)/RTT bytes per second.

Now, because the TCP throughput increases linearly between the two extreme values, we have:

average throughput of a connection to be equal to (.75*W*MSS)/RTT.

Where Maximum Segment Size (MSS) is a parameter that a computer device can receive in a single unfragmented TCP segment. It is specified in bytes.

RTT (Round-trip time) also known as the ping time is the total length of time taken to send the first packet to the destination, plus the length of time to receive the response packet.

b.. i believe would be the right one sorry if im wrong.

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