Fill in the empty function so that it returns the sum of all the divisors of a number, without including it in python

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Consider the series where in this problem you must attempt to use the ratio test to decide whether the series converges. compute enter the numerical value of the limit l if it converges, inf if it diverges to infinity, minf if it diverges to negative infinity, or div if it diverges but not to infinity or negative infinity.

Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput.find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }