Write a function to calculate the mean. Use single precision for the mean. Store the mean in memory as a float. 6. Write a function to calculate the median. Write the function so that if the length is odd, it returns the middle value as an integer. If the length is even, average the two middle values and return the median as a float. Set $v1 to be a flag to indicate whether the result was int or float

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College Computers and technology 10+5 pts

Write a program, using python, to determine the mean, median, and standard deviation of a list of numbers. In addition, count the number of duplicate numbers in the code and list any numbers that occur more than once, with the number of times the number occurs. submit a listing of your code, and the results. List = [3, 6, 7, 2, 8, 9, 2, 3, 7, 4, 5, 9, 2, 1, 6, 9, 6]

Report by Tacolover5797 05.11.2019

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The program to this question can be given as:

Program:

import math #import packages

import sys

number = [3, 6, 7, 2, 8, 9, 2, 3, 7, 4, 5, 9, 2, 1, 6, 9, 6] #define list

n = len(number) # taking length of list

print("Sample Data: ",number) #print list

#find Mean

print("Mean is: ") #message

add = sum(number) # addition of numbers.

mean = add / n #add divide by total list number.

print(str(mean)) #print mean

number.sort() #short list by using sort function

#find Median

print("Median is: ")

if n % 2 == 0: #conditional statement.

median1 = number[n//2]

median2 = number[n//2 - 1]

median = (median1 + median2)/2

else:

median = number[n//2]

print(str(median)) #print median

#find Standard deviation.

print("Standard Deviation :")

def SD(number): #define function SD

if n <= 1: #check condition

return 0.0 #return value.

mean,SD = average(number), 0.0

# find Standard deviation(SD).

for j in number:

SD =SD+(float(j)-mean)**2

#calculate Standard deviation holing in variable SD

SD =math.sqrt((SD)/float(n-1))#using math sqrt function.

return SD #return value.

def average(av): #define function average

n,mean =len(av), 0.0

if n <= 1:

return av[0] #return value.

# calculate average

for I in av:

mean +=float(i)

mean /= float(n)

return mean #return value.

print(SD(number)) #print value

Output:

Sample Data: [3, 6, 7, 2, 8, 9, 2, 3, 7, 4, 5, 9, 2, 1, 6, 9, 6]

Mean is:

5.235294117647059

Median is:

6

Standard Deviation :

2.140859045465338

Explanation:

In the above python program first, we import packages to perform maths and other functions. Then we declare the list that is number in the list the elements are given in the question. Then we declare variable n in this variable we take the number of elements present in the list and print the list first. In the list, we perform three operations that can be given as:

Mean:  

In the mean operation firstly we define the variable add in this variable we add all elements of the list by using the math sum function then we divide the number by number of elements present in the list. and sore the value in the mean variable and print it.

Median:

In the median section firstly we sort the list by using the sort function. Then we use the conditional statements for calculating median. In the if block first we modules the number by 2 if it gives 0. it calculates first and second median the add-in median .else it will print that number.

Standard Deviation:

In the standard deviation part first, we define two functions that is SD() function and average().In the SD() function we pass the list as the parameter. In this function we use the conditional statement in the if block we call the average() function and use for loop for return all values. In the average() function we calculate the average of the all number and return value. At last, we print all values.

i'm so sorry that's not a question and this isn't an answer