Suppose Host A sends two TCP segments back to back to Host B over a TCP connection. The first segment has sequence number 90; the second has sequence number 110.

a. How much data is in the first segment?

b. Suppose that the first segment is lost but the second segment arrives at B. In the acknowledgment that Host B sends to Host A, what will be the acknowledgment number?

(a) 20 bytes

(b)90

Explanation:

a. 20 bytes.

110-90= 20 Bytes

Bytes From 90-109 are in the first segment.

b. 90.

TCP uses cumulative acknowledgments, so even if it buffers the second segment, the acknowledgment is still for the first segment.

given the options, i would say your best bet is c. the modem supports up to 56 kbps, which is too low for video streaming. dial up modems use actual phone lines, which only can go up to 56 kbps as that's more than sufficient for traditional phone calls. this is also the reason why when a dial-up modem connects, you hear all those sounds. it's literally using the phone line to establish a connection.

i think the answer would be a