Given coins of denominations (value) 1 = v1 < v2< … < vn, we wish to make change for an amount A using as few coins as possible. Assume that vi’s and A are integers. Since v1= 1 there will always be a solution. Solve the coin change using integer programming. For each the following denomination sets and amounts formulate the problem as an integer program with an objective function and constraints, determine the optimal solution.

What is the minimum number of coins used in each case and how many of each coin is used? Include a copy of your code.

a) V = [1, 5, 10, 25] and A = 202.
b) V = [1, 3, 7, 12, 27] and A = 293

Answer given below

Explanation:

a) 10 coins ( 25*8 + 1*2)

b) 14 coins (27*10 + 12*1 + 7*1 + 3*1 + 1*1)

Source Code in C++:

#include <iostream>

using namespace std;

//main function

int main()

{

int n,n1;

cout << "Enter the amount : "; //taking amount as input

cin >> n;

if(n<=0)

{

cout << "Fatal Error : Input Failure." << endl;

return 1;

}

cout << "Enter the number of denominations : "; //taking number of denominations as input

cin >> n1;

if(n1<=0)

{

cout << "Fatal Error : Input Failure." << endl;

return 1;

}

int a[n1],c[n1],sum=0; //array to keep count of each amount, and sum to store total coins

cout << "Enter the denominations in descending order : ";

for(int i=0;i<n1;i++)

{

cin >> a[i];

}

for(int i=0;i<n1;i++)

{

c[i]=n/a[i];

sum=sum+c[i];

n=n%a[i];

}

for(int i=0;i<5;i++)

{

cout << a[i] << " : " << c[i] << endl;

}

return 0;

}

the answer to your question would be something called hertz. the unit of measurement called a hertz, which is one cycle per second, is used to measure clock speed. within one cycle, your computer processes, refreshes, or updates itself to the changes that it is going through. in the case of computer clock speed, one hertz equals one tick per second. the clock speed of computers is usually measured in megahertz (mhz) or gigahertz (ghz)