The pseudo-code below gives an algorithm to add two non-negative integers, m and n. Select the recurrence relation that describes the complexity of the algorithm, as a function of n, the second input variable. The running time is independent of m, the first input variable. Add(m, n) If (n = 0), Return(m) y := Add(m, n-1) Return(y + 1)

The following function returns a string of length n whose characters are all 'x'. give the order of growth (as a function of n) of the running time. recall that concatenating two strings in java takes time proportional to the sum of their lengths. public static string f(int n) { if (n == 0) return ""; if (n == 1) return "x"; return f(n/2) + f(n - n/2); } options: a) constant b) logarithmic c) linear d) linearithmic e)quadratic f)cubic g) exponential

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