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Translate the following loop into C. Assume that the C-level integer i is held in register x5,x6 holds the C-level integer called result, and x10 holds the base address of the integer MemArray. addi x6, x0, 0

addi x29, x0, 100
LOOP: ldx7, 0(x10)
addx5, x5, x7
addi x10, x10, 8
addi x6, x6, 1
bltx6, x29, LOOP

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