HELP PLEASE:
Consider the following method that is intended to test if all the Strings in the ArrayList start with an uppercase letter:

public static boolean capitalized(ArrayList a) {
/* Missing Code */
}

Which of the following could replace /* Missing Code */ so that the method works as intended?

I.

for (String s: a) {
if (s. toUpperCase().charAt(0) != s. charAt(0)) {
return true;
}
}
return false;

II.

for (String s: a) {
if (s. toUpperCase().charAt(0) != s. charAt(0)) {
return false;
}
}
return true;

III.

int flag = 1;
for (String s: a) {
if (s. toUpperCase().charAt(0) != s. charAt(0)) {
flag = 0;
}
}
return (flag == 1);

...possible answers are (I only), (II only), ( II and III), (I, II, and III), or (III only)

Create a function (prob3_6) that will do the following: input a positive scalar integer x. if x is odd, multiply it by 3 and add 1. if the given x is even, divide it by 2. repeat this rule on the new value until you get 1, if ever. your program will output how many operations it had to perform to get to 1 and the largest number along the way. for example, start with the number 3: because 3 is odd, we multiply by 3 and add 1 giving us 10. 10 is even so we divide it by 2, giving us 5. 5 is odd so we multiply by 3 and add one, giving us 16. we divide 16 (even) by two giving 8. we divide 8 (even) by two giving 4. we divide 4 (even) by two giving 2. we divide 2 (even) by 2 to give us 1. once we have one, we stop. this example took seven operations to get to one. the largest number we had along the way was 16. every value of n that anyone has ever checked eventually leads to 1, but it is an open mathematical problem (known as the collatz conjectureopens in new tab) whether every value of n eventually leads to 1. your program should include a while loop and an if-statement.