We are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 * 108meters/sec, and the distance between source and destination is 10,000 km. suppose there is only one link between source and destination. Also suppose that the entire MP3 file is sent as one packet. Suppose there are 10 TDM (Time Division Multiplexing) channels in the link. The MP3 file is sent over one of the channels. The end-to-end delay (transmission delay plus propagation delay) is.

Technician a says that with self-adjusting clutch systems, the release bearing constantly rotates. technician b says that the ball bearing portion of the release bearing should be lubricated with high-temperature grease during routine maintenance. which technician is correct?

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words.size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words.size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }

⭐️⭐️⭐️ what network is larger in size? man or wan? you ⭐️⭐️⭐️