Computers and Technology, 14.02.2020 23:07 Liannahiggins

Do you see any problem in the code of nextInOrder below:
TreeNode * nextInorder(TreeNode * p)
{
if(p->RTH == thread)
return( p->R );
else {
p = p->R;
while(p->LTH == child)
p = p->R;
return p;
}
}
► The function has no problem and will fulfill the purpose successfully.
► The function cannot be compile as it has a syntax error.
► The function has a logical problem, therefore, it will not work properly.
► The function will be compiled but will throw runtime exception immediately after the control is transferred to this function.

Answers: 3

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Do you see any problem in the code of nextInOrder below:
TreeNode * nextInorder(TreeNode * p)...

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