This problem performs elliptic curve encryption/decryption using the scheme out-
lined in section 10.4. the cryptosystem parameters are e11(1,6) and g = (2,7). b's
secret key is nb = 3. (hint: note the relationship of this system to the one discussed in
the previous question (10.14)]

a. find b's public key pb.
b. a wishes to encrypt the message pm = (10,9) and chooses the random value
k = 4. determine the ciphertext cm.

c. show the calculation by which в recovers pm from cm.

(10.> for e11(1,6) consider the point g=(2,7). compute the multiple of g from 2g through 13g.)

(a)

The formula:

→

By substituting the values, we get

(b)

As we know,

The cipher text will be:

→

By putting the values,

(c)

B Recovers will be:

→

Thus the above responses is correct.                

Learn more about cipher text here:

link

Following is the solution fr the question step by step:

a. PB = (7,2)

b. Cm = {(8,3), (10,2)}

c. Pm= (10,9)

Explanation:

answer; certification; plz check first, i believe this is correct. good luck;

only #2 represents an object at rest on a table.

in #1, there is no normal force due to the table; the object is accelerating downward.

in #3, the vertical forces are not balanced; the object is accelerating downward.

in #4, neither the vertical nor the horizontal forces are balanced. the object is accelerating upwards and to the right.