Write a method called consecutive that accepts three integers as parameters and returns true if they are three consecutive numbers—that is, if the numbers can be arranged into an order such that, assuming some integer k, the parameters’ values are k, k 1, and k 2. your method should return false if the integers are not consecutive. note that order is not significant; your method should return the same result for the same three integers passed in any order. for example, the calls consecutive(1, 2, 3), consecutive(3, 2, 4), and consecutive(–10, –8, –9) would return true. the calls consecutive(3, 5, 7), consecutive(1, 2, 2), and consecutive(7, 7, 9) would return false.

#include <iostream>

using namespace std;

void swap(int *a,int *b)

{

   int temp;

   temp=*a;

   *a=*b;

   *b=temp;

}

bool consecutive(int k1,int k2,int k3)

{

   int arr[]={k1,k2,k3};  //storing these variables into an array

   int i,j;

   for(i=0;i<3;i++)

   {

       for(j=i;j<3;j++)

       {

           if(arr[i]>arr[j])

           {

               swap(arr[i],arr[j]);  //swapping to sort these numbers

           }

       }

   }

   if((arr[1]==arr[0]+1)&&(arr[2]==arr[0]+2))  //checks if consecutive

       return true;

   else

       return false;

}

int main()

{

   int result=consecutive(6,4,5);   //storing in a result variable

   if(result==0)

       cout<<"false";

   else

       cout<<"true";

   return 0;

}

OUTPUT :

true

Explanation:

In the above code, it stores three elements into an array and then sorts the array in which it calls a method swap() which is also defined and interchanges values of 2 variables. Then after sorting these numbers in ascending order , it checks if numbers are consecutive or not, if it is true, it returns true otherwise it return false.

answer; the correct answer is technician b;

(a) oldest