On a piano, each key has a frequency, and each subsequent key (black or white) is a known amount higher. ex: the a key above middle c key has a frequency of 440 hz. each subsequent key (black or white) has a frequency of 440 * rn, where n is the number of keys from that a key, and r is 2(1/12). given an initial frequency, output that frequency and the next 3 higher key frequencies. if the input is 440, the output is: 440 493.883 523.251 554.365.note: include one statement to compute r = 2(1/12) using the pow function, then use r in the formula fn = f0 * rn. (you'll have three statements using that formula, different only in the value for n).

sample output

Enter f0 = 440

440.0,466.1637615180899, 493.8833012561241,

523.2511306011974,  554.3652619537443

Explanation:

import math                                 // math library  

def RaiseToPower():                 //  RaiseToPower method

 r = math.pow(2,1/12)               //r = 2^(1/12)

f0 = float(input('Enter f0 : '))     //input from user

//a key has a frequency,sy f0

print(f0,end=' ')                      //Display statement

 for n in range(1,5):                //Iterate the loop up to  the next 4 higher key Hz

n = f0 * math.pow(r,n)         //calculate the fn value

print(fn,end=' ')                   //Display statement

 RaiseToPower()                //Call RaiseToPower method  

answeruse the nslookup utility;