What is this system's reliability at 700 hours? component failure data is: failure rate of a = 0.0007 failures/hour reliability b = 0.92 mttf of c = 1400 hours reliability d = 0.85 show all calculation steps.

0.998

Explanation:

Given=

Reliability of B= 0.92

Reliability of D= 0.85

Hours= 700

Solution

Reliability of A = R A = e ^- 0.0007( 700) = 0.6126

Reliability of C= RC = e  ^- 700 /1400 = 0.6065

FA=  1-0.6126

FB= 1- 0.92

FC= 1- 0.6065

FD = 1- 0.85

RS = 1 - FA․ FB․ FC․ FD

FS= 1- ( 1-0.6126)( 1- 0.92)( 1- 0.6065)( 1- 0.85) = 1- 0.001829 = 0.998

inventory equipment is 1st